Poll: What Is 1/0 ? - Page 6

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Poll: What Is 1/0 ?

Good [+1]Toggle ReplyLink» neoform a répondu le Mon 12 Mar, 2007 @ 6:01pm


Coolness: 339775	Well, you're the math king.. I'm just using the stuff I was taught..

	I'm feeling you up right now..

Good [+1]Toggle ReplyLink» WassUpOnEarth a répondu le Mon 12 Mar, 2007 @ 7:36pm


Coolness: 47980	tldr

	I'm feeling overloaded right now..

Good [+1]Toggle ReplyLink» Morphine a répondu le Mon 12 Mar, 2007 @ 8:57pm


Coolness: 51080	blake and basdini are about the only ones making any sense in this thread. its fun to watch people i dont like tear into each other though

Good [+1]Toggle ReplyLink» neoform a répondu le Mon 12 Mar, 2007 @ 9:49pm


Coolness: 339775	so by deduction, that means you don't make any sense either? isn't that sorta like saying "I always lie"?

	I'm feeling you up right now..

Good [+1]Toggle ReplyLink» Morphine a répondu le Mon 12 Mar, 2007 @ 10:44pm


Coolness: 51080	well! that put ME in my place

Good [+1]Toggle ReplyLink» Screwhead a répondu le Mon 12 Mar, 2007 @ 10:47pm

Good [+1]Toggle ReplyLink» basdini a répondu le Mon 12 Mar, 2007 @ 11:23pm


Coolness: 145310	the first place to start with this problem is to admit that some functions like addition and multiplication are communitive (a + b = c, b + a = c and a x b = c, b x a = c), where as other functions like subtraction and division are not (a - b = c, b - a -does not- = c and a/b = c, b/a -does not- = c) a consequence of this is that first two are closed set functions, which means if you start with two intergers your not going to get a result that's something other than an interger. However the other two are free of this property and can quite easily map (so to speak) to other domains even irrational numbers... i'm looking around for that proof i think i saw, i ll post if i find it...

	I'm feeling surly right now..

Good [+1]Toggle ReplyLink» Morphine a répondu le Mon 12 Mar, 2007 @ 11:33pm


Coolness: 51080	commutative

Good [+1]Toggle ReplyLink» neoform a répondu le Mon 12 Mar, 2007 @ 11:48pm


Coolness: 339775	Originally Posted By MORPHINE well! that put ME in my place it did? wow, alright. good.. ?

	I'm feeling you up right now..

Good [+1]Toggle ReplyLink» Wizdumb a répondu le Tue 13 Mar, 2007 @ 1:03am


Coolness: 122420	bla bla bla

	I'm feeling camel sex right now..

Good [+1]Toggle ReplyLink» flo a répondu le Tue 13 Mar, 2007 @ 3:47am


Coolness: 146435	basdini, don't try, it is undefined in the general case as i said... you could maybe find a proof for a well-defined structure derived from the classical arithmetics, but that would not mean much in the light of the initial question. 1/0 is globally undefined, and the only way i can think of with which you could see it equal infinity would be using limits.

	I'm feeling phd powa !!! right now..

Good [+1]Toggle ReplyLink» neoform a répondu le Tue 13 Mar, 2007 @ 1:38pm


Coolness: 339775	Originally Posted By BASDINI the first place to start with this problem is to admit that some functions like addition and multiplication are communitive (a + b = c, b + a = c and a x b = c, b x a = c), where as other functions like subtraction and division are not (a - b = c, b - a -does not- = c and a/b = c, b/a -does not- = c) a consequence of this is that first two are closed set functions, which means if you start with two intergers your not going to get a result that's something other than an interger. However the other two are free of this property and can quite easily map (so to speak) to other domains even irrational numbers... i'm looking around for that proof i think i saw, i ll post if i find it... First, it's commutative, not communitive. Second, commutative simply means that the order of the 2 arguments has no effect on the outcome. Both addition/multiplication (commutative) and subtraction (not commutative) lead to closed set functions, e.g., if you input 2 integers to either addition or subtraction or multiplication, you get another integer. So the commutative property has no effect on closed set functions. Division, on the other hand, is not commutative, AND it is not closed set, in the sense that its outcome (given integer inputs) is often not an integer. Also.. what does this have to do with infinity?

	I'm feeling you up right now..

Good [+1]Toggle ReplyLink» flo a répondu le Tue 13 Mar, 2007 @ 1:49pm


Coolness: 146435	you just reformulated what he said... i think he mentioned this because with division over 2 integers (like 1 and 0), you could get something that's not integer... like infinity, for example. so this just means that with the previously stated hypothesis, dividing 2 integers may yield infinity (with respect to those few given hypothesis... which doesnt help much)

	I'm feeling phd powa !!! right now..

Good [+1]Toggle ReplyLink» neoform a répondu le Tue 13 Mar, 2007 @ 1:59pm


Coolness: 339775	i didn't read what you wrote prior to replying.. :P

	I'm feeling you up right now..

Good [+1]Toggle ReplyLink» basdini a répondu le Wed 14 Mar, 2007 @ 2:43pm


Coolness: 145310	i love how spelling something wrong on the internet means you were totally wrong to begin with...

	I'm feeling surly right now..

Good [+1]Toggle ReplyLink» neoform a répondu le Wed 14 Mar, 2007 @ 9:16pm


Coolness: 339775	Erm.. the spelling mistake didn't have much to do with the being wrong part.. :P

	I'm feeling you up right now..

Poll: What Is 1/0 ?

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