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Finding The Function Of The Form Y = Log A X
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| How does one find the function when you're given a graph and one point (9,2). vert. asymptote is 0 and the line is increasing. Anyone know? |
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| Wait. Is this an actual thread containing some form of intelligent question ?
My brain ! It huuuuuuurts !
* runs away screaming * |
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| actually, i got a reply on the rogue forums. woot. |
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| lasers! |
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| Um; 2 = ln 9a ----> e^2 = 9a -------> a = (e^2)/9
or 2 = log 9a ----> 10^2 = 9a ------> a = 100/9
O noes....the plur-star can do mathematrics |
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Coolness: 85150
| no ln in this one, a^Y = X when y = LOGa(x) got me the answer Update » No_Comply wrote on Wed Oct 22, 2008 @ 1:01pm Ok, so would LOGa(x^2/yz^3) = 2LOGaX - 3LOGaY + 3LOGaZ? |
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| I'm feeling gettin more ink soon right now.. |
Finding The Function Of The Form Y = Log A X
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